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Sketch the direction field of the differential equation. Then use it to sketch a solution curve that passes through the given point.

$ y' = y - 2x, (1,0) $

$$\begin{array}{|c|c|c|}

\hline x & y & y^{\prime}=\frac{1}{2} y \\

\hline 0 & 0 & 0 \\

0 & 1 & 0.5 \\

0 & 2 & 1 \\

0 & -3 & -1.5 \\

0 & -2 & -1 \\

\hline

\end{array}$$

Differential Equations

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University of Michigan - Ann Arbor

University of Nottingham

Idaho State University

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